PQRS and JKLR are rhombuses. Find ∠JNQ.
∠JQS
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠LKM
= 180° - 90° - 12°
= 78° (Angles sum of triangle)
∠RJQ = ∠LKM
= 78° (Corresponding angles)
∠JNQ
= 180° - 78° - 31°
= 71° (Angles sum of triangle)
Answer(s): 71°