VWXY and QRSX are rhombuses. Find ∠QUW.
∠QWY
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
∠SRT
= 180° - 90° - 16°
= 74° (Angles sum of triangle)
∠XQW = ∠SRT
= 74° (Corresponding angles)
∠QUW
= 180° - 74° - 32°
= 74° (Angles sum of triangle)
Answer(s): 74°