JKLM and DEFL are rhombuses. Find ∠DHK.
∠DKM
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
∠FEG
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠LDK = ∠FEG
= 76° (Corresponding angles)
∠DHK
= 180° - 76° - 32°
= 72° (Angles sum of triangle)
Answer(s): 72°