VWXY and QRSX are rhombuses. Find ∠QUW.
∠QWY
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
∠SRT
= 180° - 90° - 12°
= 78° (Angles sum of triangle)
∠XQW = ∠SRT
= 78° (Corresponding angles)
∠QUW
= 180° - 78° - 29.5°
= 72.5° (Angles sum of triangle)
Answer(s): 72.5°