KLMN and EFGM are rhombuses. Find ∠EJL.
∠ELN
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
∠GFH
= 180° - 90° - 12°
= 78° (Angles sum of triangle)
∠MEL = ∠GFH
= 78° (Corresponding angles)
∠EJL
= 180° - 78° - 30°
= 72° (Angles sum of triangle)
Answer(s): 72°