JKLM and DEFL are rhombuses. Find ∠DHK.
∠DKM
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
∠FEG
= 180° - 90° - 17°
= 73° (Angles sum of triangle)
∠LDK = ∠FEG
= 73° (Corresponding angles)
∠DHK
= 180° - 73° - 29.5°
= 77.5° (Angles sum of triangle)
Answer(s): 77.5°