GHJK and BCDJ are rhombuses. Find ∠BFH.
∠BHK
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠DCE
= 180° - 90° - 16°
= 74° (Angles sum of triangle)
∠JBH = ∠DCE
= 74° (Corresponding angles)
∠BFH
= 180° - 74° - 31°
= 75° (Angles sum of triangle)
Answer(s): 75°