FGHJ and ABCH are rhombuses. Find ∠AEG.
∠AGJ
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
∠CBD
= 180° - 90° - 18°
= 72° (Angles sum of triangle)
∠HAG = ∠CBD
= 72° (Corresponding angles)
∠AEG
= 180° - 72° - 30°
= 78° (Angles sum of triangle)
Answer(s): 78°