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Question

Isosceles triangle, Rhombus, Angles sum of triangle, Corresponding angles

P5.AN.JM.17083173-A1

JKLM and DEFL are rhombuses. Find ∠DHK.

4 m

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JKLM and DEFL are rhombuses. Find ∠DHK.

∠DKM
= (180° - 123°) ÷ 2
= 28.5° (Isosceles triangle)

∠FEG
= 180° - 90° - 14°
= 76° (Angles sum of triangle)

∠LDK = ∠FEG
= 76° (Corresponding angles)

∠DHK
= 180° - 76° - 28.5°
= 75.5° (Angles sum of triangle)

Answer(s): 75.5°

4 m

JKLM and DEFL are rhombuses. Find ∠DHK.

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Ischool Pte Ltd

Date:02 May 2024

Topic: ANGLES

Question Code: P5.AN.JM.17083173

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JKLM and DEFL are rhombuses. Find ∠DHK.

(4 m)

Answer(s):

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Date: 02 May 2024

Topic: ANGLES

Question Code: P5.AN.JM.17083173

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JKLM and DEFL are rhombuses. Find ∠DHK.

(4 m)

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Primary 5 ANGLES P5.AN.JM.17083173

02 May 2024, 12:20 PM

JKLM and DEFL are rhombuses. Find ∠DHK.

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ISchool Pte Ltd

Date:02 May 2024

Topic:ANGLES

Question Number:P5.AN.JM.17083173-A1

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Date:02 May 2024

Topic: ANGLES

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School:

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Date: 02 May 2024

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Ischool Pte Ltd

Date:02 May 2024

Topic: ANGLES

Question Code: P5.AN.JM.17083173

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Class:

Level:

School:

Ischool Pte Ltd

Date: 02 May 2024

Topic: ANGLES

Question Code: P5.AN.JM.17083173

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Class:

Level:

School:

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