KLMN and EFGM are rhombuses. Find ∠EJL.
∠ELN
= (180° - 123°) ÷ 2
= 28.5° (Isosceles triangle)
∠GFH
= 180° - 90° - 18°
= 72° (Angles sum of triangle)
∠MEL = ∠GFH
= 72° (Corresponding angles)
∠EJL
= 180° - 72° - 28.5°
= 79.5° (Angles sum of triangle)
Answer(s): 79.5°