PQRS and JKLR are rhombuses. Find ∠JNQ.
∠JQS
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
∠LKM
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠RJQ = ∠LKM
= 76° (Corresponding angles)
∠JNQ
= 180° - 76° - 29°
= 75° (Angles sum of triangle)
Answer(s): 75°