JKLM and DEFL are rhombuses. Find ∠DHK.
∠DKM
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠FEG
= 180° - 90° - 18°
= 72° (Angles sum of triangle)
∠LDK = ∠FEG
= 72° (Corresponding angles)
∠DHK
= 180° - 72° - 31°
= 77° (Angles sum of triangle)
Answer(s): 77°