FGHJ and ABCH are rhombuses. Find ∠AEG.
∠AGJ
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
∠CBD
= 180° - 90° - 13°
= 77° (Angles sum of triangle)
∠HAG = ∠CBD
= 77° (Corresponding angles)
∠AEG
= 180° - 77° - 31.5°
= 71.5° (Angles sum of triangle)
Answer(s): 71.5°