HJKL and CDEK are rhombuses. Find ∠CGJ.
∠CJL
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
∠EDF
= 180° - 90° - 15°
= 75° (Angles sum of triangle)
∠KCJ = ∠EDF
= 75° (Corresponding angles)
∠CGJ
= 180° - 75° - 31.5°
= 73.5° (Angles sum of triangle)
Answer(s): 73.5°