NPQR and HJKQ are rhombuses. Find ∠HMP.
∠HPR
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
∠KJL
= 180° - 90° - 13°
= 77° (Angles sum of triangle)
∠QHP = ∠KJL
= 77° (Corresponding angles)
∠HMP
= 180° - 77° - 32°
= 71° (Angles sum of triangle)
Answer(s): 71°