PQRS and JKLR are rhombuses. Find ∠JNQ.
∠JQS
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
∠LKM
= 180° - 90° - 16°
= 74° (Angles sum of triangle)
∠RJQ = ∠LKM
= 74° (Corresponding angles)
∠JNQ
= 180° - 74° - 29°
= 77° (Angles sum of triangle)
Answer(s): 77°