KLMN and EFGM are rhombuses. Find ∠EJL.
∠ELN
= (180° - 119°) ÷ 2
= 30.5° (Isosceles triangle)
∠GFH
= 180° - 90° - 13°
= 77° (Angles sum of triangle)
∠MEL = ∠GFH
= 77° (Corresponding angles)
∠EJL
= 180° - 77° - 30.5°
= 72.5° (Angles sum of triangle)
Answer(s): 72.5°