PQRS and JKLR are rhombuses. Find ∠JNQ.
∠JQS
= (180° - 123°) ÷ 2
= 28.5° (Isosceles triangle)
∠LKM
= 180° - 90° - 15°
= 75° (Angles sum of triangle)
∠RJQ = ∠LKM
= 75° (Corresponding angles)
∠JNQ
= 180° - 75° - 28.5°
= 76.5° (Angles sum of triangle)
Answer(s): 76.5°