In the figure, given that QRST is a parallelogram and VU is parallel to ST, find
- ∠QTS
- ∠SQT
- ∠QSR
(a)
∠UQR = ∠QTS = 36° (Corresponding angles)
(b)
∠SQT
= 180° - 36° - 43°
= 101° (Angles sum of triangle)
(c)
∠QSR = ∠SQT = 101° (Alternate angles)
Answer(s): (a) 36°; (b) 101°; (c) 101°