In the figure, given that JKLM is a parallelogram and PN is parallel to LM, find
- ∠JML
- ∠LJM
- ∠JLK
(a)
∠NJK = ∠JML = 30° (Corresponding angles)
(b)
∠LJM
= 180° - 30° - 32°
= 118° (Angles sum of triangle)
(c)
∠JLK = ∠LJM = 118° (Alternate angles)
Answer(s): (a) 30°; (b) 118°; (c) 118°