In the figure, given that BCDE is a parallelogram and GF is parallel to DE, find
- ∠BED
- ∠DBE
- ∠BDC
(a)
∠FBC = ∠BED = 32° (Corresponding angles)
(b)
∠DBE
= 180° - 32° - 38°
= 110° (Angles sum of triangle)
(c)
∠BDC = ∠DBE = 110° (Alternate angles)
Answer(s): (a) 32°; (b) 110°; (c) 110°