In the figure, given that ABCD is a parallelogram and FE is parallel to CD, find
- ∠ADC
- ∠CAD
- ∠ACB
(a)
∠EAB = ∠ADC = 32° (Corresponding angles)
(b)
∠CAD
= 180° - 32° - 37°
= 111° (Angles sum of triangle)
(c)
∠ACB = ∠CAD = 111° (Alternate angles)
Answer(s): (a) 32°; (b) 111°; (c) 111°