In the figure, given that NPQR is a parallelogram and TS is parallel to QR, find
- ∠NRQ
- ∠QNR
- ∠NQP
(a)
∠SNP = ∠NRQ = 34° (Corresponding angles)
(b)
∠QNR
= 180° - 34° - 41°
= 105° (Angles sum of triangle)
(c)
∠NQP = ∠QNR = 105° (Alternate angles)
Answer(s): (a) 34°; (b) 105°; (c) 105°