In the figure, given that BCDE is a parallelogram and GF is parallel to DE, find
- ∠BED
- ∠DBE
- ∠BDC
(a)
∠FBC = ∠BED = 36° (Corresponding angles)
(b)
∠DBE
= 180° - 36° - 43°
= 101° (Angles sum of triangle)
(c)
∠BDC = ∠DBE = 101° (Alternate angles)
Answer(s): (a) 36°; (b) 101°; (c) 101°