In the figure, given that ABCD is a parallelogram and FE is parallel to CD, find
- ∠ADC
- ∠CAD
- ∠ACB
(a)
∠EAB = ∠ADC = 31° (Corresponding angles)
(b)
∠CAD
= 180° - 31° - 34°
= 115° (Angles sum of triangle)
(c)
∠ACB = ∠CAD = 115° (Alternate angles)
Answer(s): (a) 31°; (b) 115°; (c) 115°