In the figure, given that JKLM is a parallelogram and PN is parallel to LM, find
- ∠JML
- ∠LJM
- ∠JLK
(a)
∠NJK = ∠JML = 31° (Corresponding angles)
(b)
∠LJM
= 180° - 31° - 39°
= 110° (Angles sum of triangle)
(c)
∠JLK = ∠LJM = 110° (Alternate angles)
Answer(s): (a) 31°; (b) 110°; (c) 110°