In the figure, given that JKLM is a parallelogram and PN is parallel to LM, find
- ∠JML
- ∠LJM
- ∠JLK
(a)
∠NJK = ∠JML = 34° (Corresponding angles)
(b)
∠LJM
= 180° - 34° - 44°
= 102° (Angles sum of triangle)
(c)
∠JLK = ∠LJM = 102° (Alternate angles)
Answer(s): (a) 34°; (b) 102°; (c) 102°