In the figure, given that EFGH is a parallelogram and KJ is parallel to GH, find
- ∠EHG
- ∠GEH
- ∠EGF
(a)
∠JEF = ∠EHG = 32° (Corresponding angles)
(b)
∠GEH
= 180° - 32° - 40°
= 108° (Angles sum of triangle)
(c)
∠EGF = ∠GEH = 108° (Alternate angles)
Answer(s): (a) 32°; (b) 108°; (c) 108°