In the figure, given that NPQR is a parallelogram and TS is parallel to QR, find
- ∠NRQ
- ∠QNR
- ∠NQP
(a)
∠SNP = ∠NRQ = 32° (Corresponding angles)
(b)
∠QNR
= 180° - 32° - 46°
= 102° (Angles sum of triangle)
(c)
∠NQP = ∠QNR = 102° (Alternate angles)
Answer(s): (a) 32°; (b) 102°; (c) 102°