In the figure, given that CDEF is a parallelogram and HG is parallel to EF, find
- ∠CFE
- ∠ECF
- ∠CED
(a)
∠GCD = ∠CFE = 32° (Corresponding angles)
(b)
∠ECF
= 180° - 32° - 33°
= 115° (Angles sum of triangle)
(c)
∠CED = ∠ECF = 115° (Alternate angles)
Answer(s): (a) 32°; (b) 115°; (c) 115°