In the figure, UVX is a triangle with VX = VU, while TUVW is a parallelogram and WVX is a straight line. Given ∠VWT = 92°, ∠SVX = 152° and ∠TSV = 49°, find
- ∠VUX
- ∠SVU
(a)
∠TWV
= ∠UVX
= 92° (Corresponding angles)
∠VUX
= (180° - 92°) ÷ 2
= 44° (Isosceles triangle)
(b)
∠SVU
= 360° - 152° - 92°
= 116° (Angles at a point)
Answer(s): (a) 44°; (b) 116°