In the figure, GHK is a triangle with HK = HG, while FGHJ is a parallelogram and JHK is a straight line. Given ∠HJF = 100°, ∠EHK = 154° and ∠FEH = 59°, find
- ∠HGK
- ∠EHG
(a)
∠FJH
= ∠GHK
= 100° (Corresponding angles)
∠HGK
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠EHG
= 360° - 154° - 100°
= 106° (Angles at a point)
Answer(s): (a) 40°; (b) 106°