In the figure, DEG is a triangle with EG = ED, while CDEF is a parallelogram and FEG is a straight line. Given ∠EFC = 92°, ∠BEG = 146° and ∠CBE = 51°, find
- ∠EDG
- ∠BED
(a)
∠CFE
= ∠DEG
= 92° (Corresponding angles)
∠EDG
= (180° - 92°) ÷ 2
= 44° (Isosceles triangle)
(b)
∠BED
= 360° - 146° - 92°
= 122° (Angles at a point)
Answer(s): (a) 44°; (b) 122°