In the figure, JKM is a triangle with KM = KJ, while HJKL is a parallelogram and LKM is a straight line. Given ∠KLH = 94°, ∠GKM = 144° and ∠HGK = 58°, find
- ∠KJM
- ∠GKJ
(a)
∠HLK
= ∠JKM
= 94° (Corresponding angles)
∠KJM
= (180° - 94°) ÷ 2
= 43° (Isosceles triangle)
(b)
∠GKJ
= 360° - 144° - 94°
= 122° (Angles at a point)
Answer(s): (a) 43°; (b) 122°