In the figure, RSU is a triangle with SU = SR, while QRST is a parallelogram and TSU is a straight line. Given ∠STQ = 92°, ∠PSU = 146° and ∠QPS = 49°, find
- ∠SRU
- ∠PSR
(a)
∠QTS
= ∠RSU
= 92° (Corresponding angles)
∠SRU
= (180° - 92°) ÷ 2
= 44° (Isosceles triangle)
(b)
∠PSR
= 360° - 146° - 92°
= 122° (Angles at a point)
Answer(s): (a) 44°; (b) 122°