In the figure, QRT is a triangle with RT = RQ, while PQRS is a parallelogram and SRT is a straight line. Given ∠RSP = 92°, ∠NRT = 146° and ∠PNR = 55°, find
- ∠RQT
- ∠NRQ
(a)
∠PSR
= ∠QRT
= 92° (Corresponding angles)
∠RQT
= (180° - 92°) ÷ 2
= 44° (Isosceles triangle)
(b)
∠NRQ
= 360° - 146° - 92°
= 122° (Angles at a point)
Answer(s): (a) 44°; (b) 122°