In the figure, QRT is a triangle with RT = RQ, while PQRS is a parallelogram and SRT is a straight line. Given ∠RSP = 100°, ∠NRT = 152° and ∠PNR = 47°, find
- ∠RQT
- ∠NRQ
(a)
∠PSR
= ∠QRT
= 100° (Corresponding angles)
∠RQT
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠NRQ
= 360° - 152° - 100°
= 108° (Angles at a point)
Answer(s): (a) 40°; (b) 108°