In the figure, HJL is a triangle with JL = JH, while GHJK is a parallelogram and KJL is a straight line. Given ∠JKG = 94°, ∠FJL = 139° and ∠GFJ = 59°, find
- ∠JHL
- ∠FJH
(a)
∠GKJ
= ∠HJL
= 94° (Corresponding angles)
∠JHL
= (180° - 94°) ÷ 2
= 43° (Isosceles triangle)
(b)
∠FJH
= 360° - 139° - 94°
= 127° (Angles at a point)
Answer(s): (a) 43°; (b) 127°