In the figure, QRT is a triangle with RT = RQ, while PQRS is a parallelogram and SRT is a straight line. Given ∠RSP = 96°, ∠NRT = 150° and ∠PNR = 49°, find
- ∠RQT
- ∠NRQ
(a)
∠PSR
= ∠QRT
= 96° (Corresponding angles)
∠RQT
= (180° - 96°) ÷ 2
= 42° (Isosceles triangle)
(b)
∠NRQ
= 360° - 150° - 96°
= 114° (Angles at a point)
Answer(s): (a) 42°; (b) 114°