In the figure, DEG is a triangle with EG = ED, while CDEF is a parallelogram and FEG is a straight line. Given ∠EFC = 100°, ∠BEG = 148° and ∠CBE = 54°, find
- ∠EDG
- ∠BED
(a)
∠CFE
= ∠DEG
= 100° (Corresponding angles)
∠EDG
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠BED
= 360° - 148° - 100°
= 112° (Angles at a point)
Answer(s): (a) 40°; (b) 112°