Question
P5.AN.JM.17083154-A1
In the figure, EFH is a triangle with FH = FE, while DEFG is a parallelogram and GFH is a straight line. Given ∠FGD = 92°, ∠CFH = 144° and ∠DCF = 59°, find
  1. ∠FEH
  2. ∠CFE
4 m
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Primary 5 ANGLES P5.AN.JM.17083154

17 May 2024, 07:43 PM

In the figure, EFH is a triangle with FH = FE, while DEFG is a parallelogram and GFH is a straight line. Given ∠FGD = 92°, ∠CFH = 144° and ∠DCF = 59°, find
  1. ∠FEH
  2. ∠CFE
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