In the figure, GHK is a triangle with HK = HG, while FGHJ is a parallelogram and JHK is a straight line. Given ∠HJF = 92°, ∠EHK = 152° and ∠FEH = 56°, find
- ∠HGK
- ∠EHG
(a)
∠FJH
= ∠GHK
= 92° (Corresponding angles)
∠HGK
= (180° - 92°) ÷ 2
= 44° (Isosceles triangle)
(b)
∠EHG
= 360° - 152° - 92°
= 116° (Angles at a point)
Answer(s): (a) 44°; (b) 116°