In the figure, KLN is a triangle with LN = LK, while JKLM is a parallelogram and MLN is a straight line. Given ∠LMJ = 100°, ∠HLN = 151° and ∠JHL = 55°, find
- ∠LKN
- ∠HLK
(a)
∠JML
= ∠KLN
= 100° (Corresponding angles)
∠LKN
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠HLK
= 360° - 151° - 100°
= 109° (Angles at a point)
Answer(s): (a) 40°; (b) 109°