In the figure, HJL is a triangle with JL = JH, while GHJK is a parallelogram and KJL is a straight line. Given ∠JKG = 100°, ∠FJL = 146° and ∠GFJ = 58°, find
- ∠JHL
- ∠FJH
(a)
∠GKJ
= ∠HJL
= 100° (Corresponding angles)
∠JHL
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠FJH
= 360° - 146° - 100°
= 114° (Angles at a point)
Answer(s): (a) 40°; (b) 114°