In the figure, CDF is a triangle with DF = DC, while BCDE is a parallelogram and EDF is a straight line. Given ∠DEB = 94°, ∠ADF = 152° and ∠BAD = 49°, find
- ∠DCF
- ∠ADC
(a)
∠BED
= ∠CDF
= 94° (Corresponding angles)
∠DCF
= (180° - 94°) ÷ 2
= 43° (Isosceles triangle)
(b)
∠ADC
= 360° - 152° - 94°
= 114° (Angles at a point)
Answer(s): (a) 43°; (b) 114°