In the figure, RSU is a triangle with SU = SR, while QRST is a parallelogram and TSU is a straight line. Given ∠STQ = 100°, ∠PSU = 144° and ∠QPS = 49°, find
- ∠SRU
- ∠PSR
(a)
∠QTS
= ∠RSU
= 100° (Corresponding angles)
∠SRU
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠PSR
= 360° - 144° - 100°
= 116° (Angles at a point)
Answer(s): (a) 40°; (b) 116°