In the figure, RSU is a triangle with SU = SR, while QRST is a parallelogram and TSU is a straight line. Given ∠STQ = 96°, ∠PSU = 137° and ∠QPS = 47°, find
- ∠SRU
- ∠PSR
(a)
∠QTS
= ∠RSU
= 96° (Corresponding angles)
∠SRU
= (180° - 96°) ÷ 2
= 42° (Isosceles triangle)
(b)
∠PSR
= 360° - 137° - 96°
= 127° (Angles at a point)
Answer(s): (a) 42°; (b) 127°