In the figure, JKM is a triangle with KM = KJ, while HJKL is a parallelogram and LKM is a straight line. Given ∠KLH = 96°, ∠GKM = 149° and ∠HGK = 49°, find
- ∠KJM
- ∠GKJ
(a)
∠HLK
= ∠JKM
= 96° (Corresponding angles)
∠KJM
= (180° - 96°) ÷ 2
= 42° (Isosceles triangle)
(b)
∠GKJ
= 360° - 149° - 96°
= 115° (Angles at a point)
Answer(s): (a) 42°; (b) 115°