In the figure, JKM is a triangle with KM = KJ, while HJKL is a parallelogram and LKM is a straight line. Given ∠KLH = 100°, ∠GKM = 139° and ∠HGK = 54°, find
- ∠KJM
- ∠GKJ
(a)
∠HLK
= ∠JKM
= 100° (Corresponding angles)
∠KJM
= (180° - 100°) ÷ 2
= 40° (Isosceles triangle)
(b)
∠GKJ
= 360° - 139° - 100°
= 121° (Angles at a point)
Answer(s): (a) 40°; (b) 121°