In the figure, RSU is a triangle with SU = SR, while QRST is a parallelogram and TSU is a straight line. Given ∠STQ = 98°, ∠PSU = 154° and ∠QPS = 50°, find
- ∠SRU
- ∠PSR
(a)
∠QTS
= ∠RSU
= 98° (Corresponding angles)
∠SRU
= (180° - 98°) ÷ 2
= 41° (Isosceles triangle)
(b)
∠PSR
= 360° - 154° - 98°
= 108° (Angles at a point)
Answer(s): (a) 41°; (b) 108°